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23x^2=46
We move all terms to the left:
23x^2-(46)=0
a = 23; b = 0; c = -46;
Δ = b2-4ac
Δ = 02-4·23·(-46)
Δ = 4232
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4232}=\sqrt{2116*2}=\sqrt{2116}*\sqrt{2}=46\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-46\sqrt{2}}{2*23}=\frac{0-46\sqrt{2}}{46} =-\frac{46\sqrt{2}}{46} =-\sqrt{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+46\sqrt{2}}{2*23}=\frac{0+46\sqrt{2}}{46} =\frac{46\sqrt{2}}{46} =\sqrt{2} $
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